Cs50 Tideman Solution -

Once you've implemented all functions, it's time to verify your solution:

for (int i = 0; i < pair_count - 1; i++)

if (locked[loser][i]) // If loser has an edge to i Cs50 Tideman Solution

Identify pairs where one candidate is preferred over another.

// Returns true if adding an edge from 'start' to 'end' creates a cycle has_cycle( Once you've implemented all functions, it's time to

The distribution code provides a skeleton with these functions:

bool vote(int rank, string name, int ranks[]) Check if from loser (A

But in step 3: Current locked: A→B, B→C. We want to lock C→A. Check if from loser (A? no, loser = A) wait, pair = (C, A): winner = C, loser = A. Check if there’s a path from loser (A) to winner (C) using current locked edges. A→B→C? Yes! So cycle would form → don’t lock.

The winner is the candidate who has no locked edges pointing to them (i.e., no column in that row has a true value in the locked table).

for (int i = 0; i < candidate_count; i++)

ranks[rank] = i; return true;